jadiesilva
Answered

Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Find reliable answers to your questions from a wide community of knowledgeable experts on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

A quadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. How many real number solutions does the equation have? help me please

Sagot :

superkoopasirf
The discriminant of a quadratic is given as [tex]b^2 - 4ac[/tex], so we know that [tex]b^2 - 4ac = -16.[/tex]

When using the quadratic formula to calculate values for [tex]x[/tex], we have to take the root of the discriminant. There is no real answer to the root of a negative number and so the equation has no real roots.

Answer:

A given quadratic equation has no real roots.

Step-by-step explanation:

Given a quadratic equation of the form [tex]ax^2+bx+c=0[/tex] has a discriminant value of –16. we have to find number of real solutions the equation have.

As given discriminant is -16

The formula to find the roots of quadratic equation by discriminant rule is

[tex]x=\frac{-b\pm\sqrt D}{2a}[/tex], [tex]\text{where D is discriminant}[/tex]

[tex]x=\frac{-b\pm\sqrt{-16}}{2a}[/tex]

[tex]x=\frac{-b\pm4i}{2a}[/tex]

which shows that neither of the solutions are real numbers.

Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.