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Sagot :
FYI this is the english section, not math.
anyway.
6 consectuve whole numbers are each divided by 6. find the sum of the resulting 6 remainders
so x, x+1, x+2, x+3, x+4, x+5
lets say that x=6
first one=no remainder
2nd=Remainder=1
3rd,R=2
4th R=3
5th R=4
6th R=5
addthem all tother (1+2+3+4+5) and get 15
if x=1 then
1st R=1
2nd R=2
3rd R=3
4th R=4
5th R=5
6th R=0
notice that we get 1+2+3+4+5 same as the first equation so the answer sill always be 15
anyway.
6 consectuve whole numbers are each divided by 6. find the sum of the resulting 6 remainders
so x, x+1, x+2, x+3, x+4, x+5
lets say that x=6
first one=no remainder
2nd=Remainder=1
3rd,R=2
4th R=3
5th R=4
6th R=5
addthem all tother (1+2+3+4+5) and get 15
if x=1 then
1st R=1
2nd R=2
3rd R=3
4th R=4
5th R=5
6th R=0
notice that we get 1+2+3+4+5 same as the first equation so the answer sill always be 15
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