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Sagot :
As you know the exterior angle formed by m< BOA is 250 degrees.
The point where C is the point of vertical angles. Vertical angles form a linear pair.
Linear pair is Always of 180 degrees so,
250 - 180 = 70 degrees
The point where C is the point of vertical angles. Vertical angles form a linear pair.
Linear pair is Always of 180 degrees so,
250 - 180 = 70 degrees
we know that
The measure of the external angle is the semidifference of the arcs that it covers.
so
[tex] m\ angle\ BCA= \frac{1}{2} *(arc\ BOA-arc\ BA)\\\\ m\ angle\ BCA= \frac{1}{2} *(250-110)\\ \\ m\ angle\ BCA=70\ degrees [/tex]
therefore
the answer is
The measure of angle BCA is equal to [tex] 70\ degrees [/tex]
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