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Sagot :
[tex]find\ \frac{2}{5}\ \ of\ \ \frac{3}{4}\\\\
\frac{2}{5}*\frac{3}{4}=\frac{6}{20}=\frac{3}{10}\\\\
\frac{3}{10}\ of\ cereal\ were\ eaten.[/tex]
the box contains cereal. Only 3/4 of the box has cereal remaining.
From the remaining cereal fraction, 2/5th is consumed.
then the portion of cereal consumed is
[tex] \frac{2}{5} of \frac{3}{4} [/tex]
when the 'of' function is used it means the fractions should be multiplied
then numerators should be multiplied by numerators and denominators by denominators
[tex] \frac{2*3}{5*4} = \frac{6}{20} [/tex]
this can be further simplified by dividing both numerator and denominator by a factor common to both , in this case both 6 and 20 are divisible by 2
[tex] \frac{6}{20} / 2 = \frac{3}{10} [/tex]
answer is 3/10th of the box is consumed
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