Answered

At Westonci.ca, we provide clear, reliable answers to all your questions. Join our vibrant community and get the solutions you need. Experience the ease of finding reliable answers to your questions from a vast community of knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

solve the equation 2x^2-x=1

Sagot :

luana
[tex]2x^2-x=1\ \ \ | subtract\ 1\\\\ 2x^2-x-1=0\\\\use\ factorization:\\ write\ -x\ as\ x-2x\\\\ 2x^2+x-2x-1=0\\\\ x(2x+1)-1(2x-1)=0\\\\ (x-1)(2x+1)=0\\\\ x=1\ \ \ or\ \ \ 2x=-1\\\\ x=1\ \ \ or \ \ \ x=-\frac{1}{2}[/tex]
FirstSineOfMadness
First move all terms to the same side.
2x^2-x-1=0
Factor this to get
(2x+1)(x-1)=0
Separate into
2x+1=0 and x-1=0
Solve these two to get
X=-1/2 or x=1
Final answer:
X=-1/2 or x=1
Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.