Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

solve the equation 2x^2-x=1

Sagot :

luana
[tex]2x^2-x=1\ \ \ | subtract\ 1\\\\ 2x^2-x-1=0\\\\use\ factorization:\\ write\ -x\ as\ x-2x\\\\ 2x^2+x-2x-1=0\\\\ x(2x+1)-1(2x-1)=0\\\\ (x-1)(2x+1)=0\\\\ x=1\ \ \ or\ \ \ 2x=-1\\\\ x=1\ \ \ or \ \ \ x=-\frac{1}{2}[/tex]
FirstSineOfMadness
First move all terms to the same side.
2x^2-x-1=0
Factor this to get
(2x+1)(x-1)=0
Separate into
2x+1=0 and x-1=0
Solve these two to get
X=-1/2 or x=1
Final answer:
X=-1/2 or x=1
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.