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solve the equation using any method you prefer. Give imaginary roots.[tex]3a^2+4=2a[/tex]

Sagot :

konrad509
[tex]3a^2+4=2a\\ 3a^2-2a+4=0\\ \Delta=(-2)^2-4\cdot3\cdot4=4-48=-44\\ \sqrt{\Delta}=\sqrt{-44}=2\sqrt{11}i\\ x_1=\frac{-(-2)-2\sqrt{11}i}{2\cdot3}=\frac{2-2\sqrt{11}i}{6}=\frac{1-\sqrt{11}i}{3}\\ x_2=\frac{-(-2)+2\sqrt{11}i}{2\cdot3}=\frac{2+2\sqrt{11}i}{6}=\frac{1+\sqrt{11}i}{3}\\[/tex]
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