Answered

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preform the operation (answer in a+bi form) (i meaning imaginary number)
[tex] \frac{2+i}{2-1} [/tex]

Sagot :

konrad509
[tex]\frac{2+i}{2-i}=\frac{(2+i)^2}{(2-i)(2+i)}=\frac{4+4i-1}{4+1}=\frac{3+4i}{5}=\frac{3}{5}+\frac{4}{5}i[/tex]
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