Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
[tex]C_{m}=\frac{n}{V_{r}}\\\\
m=\frac{m}{M}\\\\
C_{m}=\frac{m}{MV_{r}} \ \ \ \ \Rightarrow \ \ \ \ m=C_{m}MV_{r}}\\\\
C_{m}=0.25\frac{mol}{L}\\
M_{CaBr_{2}}=200\frac{g}{mol}\\
V_{r}=50mL=0.05L\\\\
m=0.25\frac{mol}{L}*200\frac{g}{mol}*0.05L= \emph{\textbf{2.5g}}[/tex]
The mass of the compound can be calculated by the molarity. The mass of the calcium bromide in the given solution is 2.5 g.
The mass of the given compound can be calculated by the molarity formula,
[tex]\bold {M = \dfrac {w}{m\times v} \times 1000}\\\\\bold {w = \dfrac {M\times m\times v}{ 1000}}[/tex]
Where,
M- molarity of the solution = 0.25 M
w - given mass =?
m -molar mass of Calcium bromide = 200 g/mol
v- volume in mL= 50 mL
Put the values in the formula,
[tex]\bold {w = \dfrac {0.25\times 200\times 50}{ 1000}}\\\\\bold {w = 2.5\ g}[/tex]
Therefore, the mass of the calcium bromide in the given solution is 2.5 g.
To know more about Molarity,
https://brainly.com/question/12127540
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.