Answered

Welcome to Westonci.ca, your go-to destination for finding answers to all your questions. Join our expert community today! Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

A 0.63kg mass rests on top of a vertical spring with spring constant 65N/m. When the mass sits at rest, determine the distance that the spring is compressed from it's equilibrium position.

Sagot :

AL2006
The mass will sag lower and lower and compress the spring, until the
upward force of the spring is equal to the weight of the mass.  When
that happens, the two forces on the mass (gravity and spring) will be
balanced, and the mass will stop sinking.

-- The weight of the mass is (mass) x (gravity) = (0.63) x (9.8) Newtons.

-- The distance that the spring is compressed is  1 meter / 65 newtons.

(1 meter/65 newtons) x (0.63 x 9.8) newtons = 0.095 meter = 9.5 centimeters
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.