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Sagot :
The equation is 54=(n)+(n+1)+(n+2)
Which simplifies to 54=3n+3
Subtract 3 from each side to get 51=3n
Divide each side by 3 to get 17=n
Then you substitute 17 for n to get 17 (n) and 18 (n+1) and 19 (n+2).
Which simplifies to 54=3n+3
Subtract 3 from each side to get 51=3n
Divide each side by 3 to get 17=n
Then you substitute 17 for n to get 17 (n) and 18 (n+1) and 19 (n+2).
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