Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

The reaction described in Part A required 3.98L of calcium chloride. What is the concentration of this calcium chloride solution?

Sagot :

Joel0920
You need to find the moles of CaCl, you can either do a grams to mol conversion, OR, you can do the equation used in A without the last step which was converting it into the grams on CaCl. You get .00848146 mol CaCl. with that you can find the concentration using the molarity equation which is M=mol/L. M=.000848146mol/3.98 L. M=0.000213 or your teacher may want you to write it 0.000213 M CaCl. Hope I helped :)
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.