Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
I'm not sure if the answer is right, but here you go.
y=mx+b
'm' is for gradient of the line. First, calculate the gradient.
Let's use (6,15) and (8,21)
Gradient, m = [tex]y_{2} [/tex] - [tex] y_{1} [/tex]
--------------
[tex] x_{2} [/tex] - [tex] x_{1} [/tex]
= 21 - 15 = 6 = 3
----------- ----
8 - 6 2
Therefore, m = 3 . Now let's search 'b' .
Let's use (6,15) again. Substitute it into the equation.
y=mx+b
15 = 3 (6) + b
b = -3
Thus, the equation : y=3x -3
y=mx+b
'm' is for gradient of the line. First, calculate the gradient.
Let's use (6,15) and (8,21)
Gradient, m = [tex]y_{2} [/tex] - [tex] y_{1} [/tex]
--------------
[tex] x_{2} [/tex] - [tex] x_{1} [/tex]
= 21 - 15 = 6 = 3
----------- ----
8 - 6 2
Therefore, m = 3 . Now let's search 'b' .
Let's use (6,15) again. Substitute it into the equation.
y=mx+b
15 = 3 (6) + b
b = -3
Thus, the equation : y=3x -3
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.