a student 1/3 of clay and a other student has 5/8 of clay what do you do if you have to divide it

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22-11-2014
Mathematics

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a student 1/3 of clay and a other student has 5/8 of clay what do you do if you have to divide it

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apologiabiology apologiabiology · Answer 1 · 2014-11-22T20:19:38-05:00

apologiabiology apologiabiology

22-11-2014

so basically this qestion is asking you to add 1/3 and 5/8 together and divide the result by 2 so first get the denomenator (bottom number ) the same
1/3=8/24
5/8=15/24
8/24+15/24=23/24
divide this by 2 and get
23/48 of clay

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a student 1/3 of clay and a other student has 5/8 of clay what do you do if you have to divide it

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