cpearson1603
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Laura's uncle donated 120 cans of juice and 90 packs of cheese crackers for the school picnic. Each student is to receive the same number of cans of juice and the same number of packs of crackers. What is the largest number of students that can come to the picnic and share the food equally? How many cans of juice and packs of cheese crackers will each student get?

Answer: The largest number of students that can come to the picnic is( ) students. Each student will get ( )cans of juice and( ) packs of cheese crackers.

Sagot :

Joel0920

Ok, First you have to find the GCF of 120 and 90. When I got the answer I got a GCF of 30. I got 30 by multiplying all the number prime numbers 120 and 90 had, 2×3×5=30  What I did next was  divide thirty by the number of  cracker and also by the number of can of juice.

120÷30= 4

90÷30=  3

So as you can see there could be a maximum 30 of kid's. Each of the kids would receive 4 cans of juice and 3 packs of cheese crackers.


I hope you enjoyed my explanation. :)

apologiabiology
so we want to know what the largest number that can go into both 90 and 120 aka the Greatest common factor or GCF

so 90=3*3*2*5
120=2*2*3*2*5
the number in common are 3*2*5
if we multiply that out we get 30
so 30 is the maximum number of students so that they all share equally so
90/30=3 so each student gets 3 packs of cheese crackers
120/30=4 so each student gets 4 cans of juice
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.