Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
you have to put the equation in slope-intercept form, which is y=mx+b, so you have to subract 10x from both sides to get 6y=-10x+100, then divide all the terms by 6 to get y=-5/3x+16 2/3. Then all you do is graph 16 2/3 on the y axis and from that point do the slope, which is -5/3, so you have to go down on the y axis 5, and over to the right 3, and put a point. Then you just repeat this to get a few more points to be able to draw a line. (I hope this helps! sorry if i confused you even more, I'm not the best at explaining things, but hopefully I cleared things up a bit for you)
[tex]standard\ equation\ linear :\\y=ax+b\\\\10x + 6y =100\ \ |\ subtract\ 10x\ to\ both\ sides \\\\6y=-10x+100\ \| \ divide \ each \ term \ by \ 2\\\\3y=-5x+50| \ divide \ each \ term \ by \ 3 \\\\y=-\frac{5}{3}x+\frac{50}{3}[/tex]
[tex]x=1 \ \ \to\ y=-\frac{5}{3}*1+\frac{50}{3} =-\frac{5}{3} +\frac{50}{3}= \frac{45}{3}=15\\\\ x=10 \ \ \to\ y=-\frac{5}{3}*10+\frac{50}{3}=-\frac{50}{3} +\frac{50}{3}=0[/tex]
[tex]x=1 \ \ \to\ y=-\frac{5}{3}*1+\frac{50}{3} =-\frac{5}{3} +\frac{50}{3}= \frac{45}{3}=15\\\\ x=10 \ \ \to\ y=-\frac{5}{3}*10+\frac{50}{3}=-\frac{50}{3} +\frac{50}{3}=0[/tex]

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.