Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Two welders working together can complete a job in 6 h. One of the welders, working alone, can complete the task in 15 h. How long would it take the second welder, working alone, to complete the task?

Sagot :

MichaelLiu
ur asking a bunch of these kind of rate problems xD
[tex]6 ( \frac{1}{15} + \frac{1}{x} )=1[/tex]
In 6 hrs, the welder who does 1/15 of the job in 1 hr and the welder who does 1/x in 1 hr, complete the job (6 hrs.)
[tex] \frac{1}{15} + \frac{1}{x} = \frac{1}{6} [/tex]
Multiply 30 on both sides to cancel out the fractions and we get:
[tex]2 + \frac{30}{x} =5[/tex]
Solving for x:
30/x=3
3x=30
x=10
The second welder would take 10 hours.

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.