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What is the molarity of 5.00 g of NaOH in 750.0 mL of solution?

Sagot :

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m = 5g M = 40g/mol n = m/M = 5g/40g/mol = 0.08mol Cm = n/V n = 0.08mol V = 750mL = 0.75L Cm = 0.08/0.75L = 0.107mol/L
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