Answered

Westonci.ca is the ultimate Q&A platform, offering detailed and reliable answers from a knowledgeable community. Get quick and reliable answers to your questions from a dedicated community of professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

what is the maximum volume of 0.788M CaCl2 solution that can be prepared using 85.3g CaCl2

Sagot :

Concentration=moles/volume
Volume=moles/concentration
To find the number of moles, you divide the mass of CaCl2 by its molar mass. The molar mass of CaCl2 is: 2x35.45(molar mass Cl) + 40.08(molar mass Ca)
Molar mass= 110.98g/mol
Moles=m/molar mass
Moles=85.3/110.98
Moles=0.7686069562
Then you calculate the volume:
Volume= 0.7686069562/0.778
Volume= 0.9879266789L
=0.988L
Therefor the max volume that can be prepared is 0.998L

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.