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Sagot :
[tex]5x-2y=11\\\\y=ax+b\\\\
Line\ is\ perpendicular when\ new\ a=-\frac{1}{a_1}\\\\
-2y=11-5x\ \ \ | divide\ by\ -2\\\\
\boxed{y=\frac{5}{2}x-\frac{11}{2}}\\\\Solution\ is\ D[/tex]
Answer:
the answer is c
Step-by-step explanation:
5x-2y=11
-5x to 5x and 11
-2y=-5x+11
divide -2 to -2, 5x, and 11
y= -5/2+11/-2
-5/2 is the slope but -2/5 is the slope of a line perpendicular
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