Answered

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(1-sin^2x/cosx)= (sin2x/2sinx)

Sagot :

AL2006
Left side:

1-sin²(x) = cos²(x)

1-sin²(x) / cos(x) = cos²(x) / cos(x) = cos(x)


Right side:

sin(2x) = 2 sin(x) cos(x)

sin(2x) / 2 sin(x) = 2 sin(x) cos(x) / 2 sin(x) = cos x
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