Answered

Welcome to Westonci.ca, your ultimate destination for finding answers to a wide range of questions from experts. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

really stuck on this problem. Everyone I asked for help is stuck too.

Simplify
(x^-2 - y^-2) / (x^-1 - y^-1)

Sagot :

apologiabiology
so negative exponents mean reciprocals so x^-1=1/(x^1)

x^-2=1/(x^2)
x^-2=1/(y^2)
so ([1/(x^2)]-[1/(y^2]) is the diffarence of two perfect squares which is (x^-2-y^-2)=(1/x-1/y)(1/x+1/y)

so
that equals (1/x-1/y)(1/x+1/y)

(x^-1)=1/x
y^-1=1/y
the bottom is (1/x-1/y)
so the equation is
[(1/x-1/y)(1/x+1/y)]/(1/x-1/y)
we can cancell out the (1/x-1/y) on the top and the bottom and be left with
(1/x-1/y)/1 or 1/x-1/y
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.