At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
[tex]General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (3,-5),\ (-5,3)\ into\ equation\\\\
\left \{ {{-5=3a+b}\ \ \ \ \atop {3=-5a+b\ |*-1}} \right.\\\\ \left \{ {{-5=3a+b} \atop {-3=5a-b}} \right. \\+----\\\\-8=8a\ \ \ |:8\\a=-1\\\\-5=3\cdot(-1)+b\\-5=-3+b\\-5+3=b\\b=-2\\\\y=-x-2[/tex]
Steps:
1. First you have to find the slope
3+5= 8 -5-3=-8 Your slope is -1
2. You plug in one of the points into the point slope form
Y1-Y2=m(x-x1)
Y-3=-1(x+5)
Y-3=-1x+-5
3. Then, you add three to each side
Y=-1x+ (-2)
1. First you have to find the slope
3+5= 8 -5-3=-8 Your slope is -1
2. You plug in one of the points into the point slope form
Y1-Y2=m(x-x1)
Y-3=-1(x+5)
Y-3=-1x+-5
3. Then, you add three to each side
Y=-1x+ (-2)
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.