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Sagot :
Mark has: 1 1/3 = 4/3 gallons of Yellow
1 1/4 = 5/4 gallons of Green
7/8 gallons of Blue.
Total = (4/3 + 5/4 + 7/8) LCM = 24
= (32 + 30 + 21)/24 = 83/24 Gallons of Paint in total.
If he used 3/4 of each, he would have (1 - 3/4) = 1/4 of each left.
Therefore gallons left = 1/4 * (83/24) = 83/96 gallons left.
= 0. 8646 gallons left in total.
1 1/4 = 5/4 gallons of Green
7/8 gallons of Blue.
Total = (4/3 + 5/4 + 7/8) LCM = 24
= (32 + 30 + 21)/24 = 83/24 Gallons of Paint in total.
If he used 3/4 of each, he would have (1 - 3/4) = 1/4 of each left.
Therefore gallons left = 1/4 * (83/24) = 83/96 gallons left.
= 0. 8646 gallons left in total.
we have
Yellow paint
[tex] 1\frac{1}{3} =(3*1+1)/3\\ \\ =\frac{4}{3} gal [/tex]
Find the
amount of yellow paint left after painting the mural
[tex] (\frac{4}{3} -\frac{3}{4} )=(4*4-3*3)/12\\ \\ =\frac{7}{12} gal [/tex]
Green paint
[tex] 1\frac{1}{4} =(4*1+1)/4\\ \\ =\frac{5}{4} gal [/tex]
Find the
amount of green paint left after painting the mural
[tex] (\frac{5}{4} -\frac{3}{4} )=(5-3)/4\\ \\ =\frac{2}{4} gal [/tex]
Blue paint
[tex] \frac{7}{8}gal [/tex]
Find the
amount of blue paint left after painting the mural
[tex] (\frac{7}{8} -\frac{3}{4} )=(7-2*3)/8\\ \\ =\frac{1}{8} gal [/tex]
Find the
total amount of paint left after painting the mural
[tex] \frac{7}{12} +\frac{2}{4} +\frac{1}{8} =\frac{(2*7+6*2+3*1)}{24} \\ \\ =\frac{29}{24} gal [/tex]
[tex] \frac{29}{24} =1\frac{5}{24} gal [/tex]
therefore
the answer is
[tex] 1\frac{5}{24} gal [/tex]
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