Wisteria
Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

A piece of art is in the shape of an equilateral triangle with sides of 25in. Find the area of the piece of art. Round your answer to the nearest tenth. Answers: A:221in^2 B:270in^2 C: 541.3in^2 and D: none of these

Sagot :

A=[tex] \sqrt{3}/4 [/tex] * side length^2
A=270.663
The answer is B.
To find the area of a triangle you need the formula (base*height)/2.  We know the base is 25in however we need to find the height to have everything for the formula. If you draw a picture of this equilateral triangle so the bottom is a flat side, the height goes straight up the middle, splitting the triangle into two equal pieces.  However, to find the height, you have to use Pythagoras's theorem (a^2+b^2=c^2).  c is the hypotenuse so that is the 25in, a is half the width of the base, 12.5in, and b is what you are looking for.  When solved, b becomes about 21.65, or if you have to be exact- sqrt{468.75}.  Then plug this in for the height in the original equation.
(25*sqrt{468.75})/2≈270.63 in^2
We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.