Wisteria
Answered

Discover a wealth of knowledge at Westonci.ca, where experts provide answers to your most pressing questions. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

A piece of art is in the shape of an equilateral triangle with sides of 25in. Find the area of the piece of art. Round your answer to the nearest tenth. Answers: A:221in^2 B:270in^2 C: 541.3in^2 and D: none of these

Sagot :

A=[tex] \sqrt{3}/4 [/tex] * side length^2
A=270.663
The answer is B.
To find the area of a triangle you need the formula (base*height)/2.  We know the base is 25in however we need to find the height to have everything for the formula. If you draw a picture of this equilateral triangle so the bottom is a flat side, the height goes straight up the middle, splitting the triangle into two equal pieces.  However, to find the height, you have to use Pythagoras's theorem (a^2+b^2=c^2).  c is the hypotenuse so that is the 25in, a is half the width of the base, 12.5in, and b is what you are looking for.  When solved, b becomes about 21.65, or if you have to be exact- sqrt{468.75}.  Then plug this in for the height in the original equation.
(25*sqrt{468.75})/2≈270.63 in^2
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.