Wisteria
Answered

Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A piece of art is in the shape of an equilateral triangle with sides of 25in. Find the area of the piece of art. Round your answer to the nearest tenth. Answers: A:221in^2 B:270in^2 C: 541.3in^2 and D: none of these

Sagot :

A=[tex] \sqrt{3}/4 [/tex] * side length^2
A=270.663
The answer is B.
To find the area of a triangle you need the formula (base*height)/2.  We know the base is 25in however we need to find the height to have everything for the formula. If you draw a picture of this equilateral triangle so the bottom is a flat side, the height goes straight up the middle, splitting the triangle into two equal pieces.  However, to find the height, you have to use Pythagoras's theorem (a^2+b^2=c^2).  c is the hypotenuse so that is the 25in, a is half the width of the base, 12.5in, and b is what you are looking for.  When solved, b becomes about 21.65, or if you have to be exact- sqrt{468.75}.  Then plug this in for the height in the original equation.
(25*sqrt{468.75})/2≈270.63 in^2
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.