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a boy is 24 years younger than his father. In 2 years time the sun of their ages will be 40. Find the present ages of father and son

Sagot :

apologiabiology
ooh fun

x=boy
y=father
x+24=y
(x+2)+(y+2)=40
subsitute x+24=y into equation
x+2+x+24+2=40
add like terms
2x+28=40
subtract 28 from both sides
2x=40
divide both sides by 2
x=son now=20
father=son+24
father=20+24=44

father=44
son=20
olemakpadu
Let the age of the boy be x.
Therefore the age of the father = x + 24.  (The boy is 24 years younger implies that 
                                                           his father is older by 24 years).

In 2 years time:
The boy will be = (x +2).
The father will be (x +24 +2) = (x + 26).

Sum of their ages = 40.
Therefore            (x+2) + (x + 26) = 40.
                           x + x + 2 + 26 = 40
                                      2x + 28 = 40
                                              2x = 40 -28
                                               2x = 12.
                                                 x = 12/2 = 6.    x =6.
Present ages =  x , x +24.  =  6,  (6 +24) =    6, 30.
Boy = 6 years old.
Father = 30 years old.
Cheers.
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