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What are the coordinates of the turning point of the graph of y=2x^2-4x+1?

Sagot :

x=-b/2a=-(-4)/2(2)=4/4=1
y=2(1)^2-4(1)+1=-1
so the point is (1,-1)

An equation is formed of two equal expressions. The coordinates of the turning point of the graph of y=2x²-4x+1 are (1,-1).

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.


The turning point of the graph is the vertex of the parabolic graph. Therefore, the coordinates of the turning point of the graph of y=2x²-4x+1 are (1,-1).

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