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Sagot :
Call the first odd number x.
That means the next odd number would be x+2.
For example, if the first odd number is 9 then the next one would be 11, which is why it is plus 2. Okay?
So then, x+x+2=128
2x+2=128
2x=126
x=63
x+2=65
The two consecutive numbers are 63 and 65
That means the next odd number would be x+2.
For example, if the first odd number is 9 then the next one would be 11, which is why it is plus 2. Okay?
So then, x+x+2=128
2x+2=128
2x=126
x=63
x+2=65
The two consecutive numbers are 63 and 65
[tex] 2n+1;\ 2n+3-2\ consecutive\ odd\ integers\\where\ n\ is\ natural\ number\\\\(2n+1)+(2n+3)=128\\2n+1+2n+3=128\\(2n+2n)+(1+3)=128\\4n+4=128\ \ \ \ |subtract\ 4\ from\ both\ sides\\4n=124\ \ \ \ \ |divide\ both\ sides\ by\ 44\\n=62\\\\Answer:\ \boxed{63;\ 65}[/tex]
[tex]other\ solution:\\\\128:2=64\\\\answer:\\\\64+1=\fbox{65}\\64-1=\fbox{63}[/tex]
[tex]other\ solution:\\\\128:2=64\\\\answer:\\\\64+1=\fbox{65}\\64-1=\fbox{63}[/tex]
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