Answered

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1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15

Sagot :

MrRoyal

Answer:

[tex]\frac{4+16a^3+23a^3}{a^2}[/tex]

Step-by-step explanation:

Given

[tex]1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15[/tex]

Required

Simplify

[tex]1/a^2-3a+2 + 1/a^2-5a+6 + 2/a^2-8a+15[/tex]

Collect Like Terms

[tex]1/a^2 + 1/a^2 + 2/a^2-3a-5a-8a+2+6+15[/tex]

[tex]1/a^2 + 1/a^2 + 2/a^2-16a+23[/tex]

Add Fractions:

[tex]\frac{1+1+2}{a^2} + 16a + 23[/tex]

[tex]\frac{4}{a^2} + 16a + 23[/tex]

This can be further expressed as:

[tex]\frac{4+16a^3+23a^3}{a^2}[/tex]

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