Answer:
The value is [tex]R = 0.321 \ \Omega[/tex]
Explanation:
From the question we are told that
The diameter is [tex]d = 8.252 \ mm = 0.008252 \ m[/tex]
The length of the wire is [tex]l = 1.0 \ km = 1000 \ m[/tex]
Generally the cross sectional area of the copper wire is mathematically represented as
[tex]A = \pi * \frac{d^2}{4}[/tex]
=> [tex]A = 3.142 * \frac{ 0.008252^2}{4}[/tex]
=> [tex]A = 5.349 *10^{ - 5} \ m^2[/tex]
Generally the resistance is mathematically represented as
[tex]R = \frac{\rho * l }{A }[/tex]
Here [tex]\rho[/tex] is the resistivity of copper with the value [tex]\rho = 1.72*10^{-8} \ \Omega \cdot m[/tex]
=> [tex]R = \frac{1.72 *10^{-8} * 1000 }{5.349 *10^{ - 5} }[/tex]
=> [tex]R = 0.321 \ \Omega[/tex]
