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Square ABCD was translated using the rule (x. y) «-4,y + 15) to form A'B'CD. What are the coordinates of point
D in the pre-image if the coordinates of point D' in the image are (9, -8)?
TE
O (13, -23)
(5, 7)
O (18, 1)
O (6,4)

Sagot :

MrRoyal

Answer:

[tex](13,-23)[/tex]

Step-by-step explanation:

Given

Translation: [tex](x,y) -> (x-4,y+15)[/tex]

Required

Determine the pre-image of (9,-8)

In (9,8)

[tex]x = 9[/tex] and [tex]y = -8[/tex]

So:

[tex](x,y) -> (x-4,y+15)[/tex]

Becomes

[tex](9,8) ->(x-4,y+15)[/tex]

By comparison:

[tex]x - 4 = 9[/tex]

[tex]y + 15 = 8[/tex]

Solving for (x):

[tex]x - 4 = 9[/tex]

[tex]x = 9 + 4[/tex]

[tex]x = 13[/tex]

Solving for (y):

[tex]y + 15 = -8[/tex]

[tex]y = -8 - 15[/tex]

[tex]y = -23[/tex]

Hence, the pre -image has a coordinate of [tex](13,-23)[/tex]

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