Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Experience the convenience of getting reliable answers to your questions from a vast network of knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Step-by-step explanation:
Let the given ratio be pk : qk .
So , here the quadratic equation is lx² + nx + n = 0. With respect to Standard form ax² + bx + c = 0.
We have ,
- a = l
- b = n
- c = n
→ Sum of roots = -b/a = -n/l = qk + pk
→ Product of roots = c/a = n/l = k²pq .
[tex]=> \dfrac{n}{l} = \dfrac{k^2}{pq} \\\\=> k^2 =\dfrac{n}{pql} [/tex]
And here pk and qk is a root of the quadratic equation ,
[tex]=> lx^2 + nx + n = 0 \\\\=> l(pk)^2 + n(pk) + n = 0\\\\=> lp^2k^2+npk + n = 0 \\\\=> lp^2\bigg( \dfrac{n}{pql} \bigg) + np\bigg(\sqrt{\dfrac{n}{pql}} \bigg) + n = 0 \\\\ => n\bigg\{\dfrac{p}{q}+\sqrt{\dfrac{np}{lq}}+1\bigg\} = 0 \\\\=> \dfrac{p}{q}+\sqrt{\dfrac{np}{lq}}+1 =0\\\\=>\sqrt{\dfrac{p}{q}} \bigg( \dfrac{q}{p}+\sqrt{\dfrac{np}{lq}}+1\bigg) = 0 \\\\=> \sqrt{\dfrac{p}{q}}+ \sqrt{\dfrac{q}{p}}+ \sqrt{\dfrac{n}{l}}=0 \\\\\boxed{\red{\bf\longmapsto \sqrt{\dfrac{p}{q}}+ \sqrt{\dfrac{q}{p}} = - \sqrt{\dfrac{n}{l}}}} [/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.