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Sagot :
Answer:
The ratio of the time period of the proton to the electron is 1835.16.
Explanation:
Given that,
Two particles, an electron and a proton, move in a circular path in a uniform magnetic field of intensity B=1.23 T
We need to find the ratio between the time period of the proton Tp to the electron Te.
The time period in magnetic field is given by :
[tex]T=\dfrac{2\pi m}{qB}[/tex]
For proton, time period is :
[tex]T_P=\dfrac{2\pi m_P}{q_pB}\ ....(1)[/tex]
For an electron, the time period is :
[tex]T_e=\dfrac{2\pi m_e}{q_eB}\ ....(2)[/tex]
From equation (1) and (2) :
[tex]\dfrac{T_p}{T_e}=\dfrac{\dfrac{2\pi m_p}{q_pB}}{\dfrac{2\pi m_e}{q_eB}}\\\\As\ q_e=q_p\\\\\dfrac{T_p}{T_e}=\dfrac{m_p}{m_e}\\\\=\dfrac{1.67\times 10^{-27}}{9.1\times 10^{-31}}\\\\=1835.16[/tex]
So, the ratio of the time period of the proton to the electron is 1835.16.
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