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Sagot :
Answer:
Percent yield = 87.5%
Explanation:
Given data:
Number of moles of Fe(NO₃)₃ = 2.5 mol
Number of moles of Na₂CO₃ = 3.6 mol
Actual yield of NaNO₃ = 6.3 mol
Percent yield of NaNO₃ = ?
Solution:
Chemical equation:
2Fe(NO₃)₃ + 3Na₂CO₃ → Fe₂(CO₃)₃ + 6NaNO₃
now we will compare the moles of both reactant with NaNO₃.
Fe(NO₃)₃ : NaNO₃
2 : 6
2.5 : 6/2×2.5 = 7.5
Na₂CO₃ : NaNO₃
3 : 6
3.6 : 6/3×3.6 = 7.2
Theoretical yield of NaNO₃ is 7.2 mol.
Percent yield:
Percent yield = actual yield / theoretical yield ×100
Percent yield = 6.3 mol / 7.2mol ×100
Percent yield = 87.5%
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