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for what value of “x” is the figure the given special parallelogram?


For What Value Of X Is The Figure The Given Special Parallelogram class=

Sagot :

Dead3ill

Answer:

x = 6

Step-by-step explanation:

(In reference to my diagram.... my diagram is similar to the diagram in the question)

We know that diagonals of a square bisect each other at right angles.

In ΔBOC ,

•OB = OC (Diagonals of square bisect each other)

=> ∠OBC = ∠OCB = (7x + 3)°        (∵ OB = OC)

• ∠BOC = 90° (Diagonals intersect at right angles)

Using angle sum property of triangle ,

∠OBC + ∠OCB + ∠BOC = 90°

[tex] = > 7x + 3 + 7x + 3 + 90 = 180[/tex]

[tex] = > 14x + 6 = 180 - 90 = 90[/tex]

[tex] = > 14x = 90 - 6 = 84[/tex]

[tex] = > x = \frac{84}{14} = 6[/tex]

View image Dead3ill
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