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Calculate the mass of 0.2 moles of zinc nitrate.

Sagot :

rebeccarayshma

Answer:

mass = 37.8 g

Explanation:

mass = mol × molar mass

mol = 0.2

molar mass = Zn(NO3)2

Zn = 65

N = 14

O = 16

substitute the values into Zn(NO3)2

Zn(NO3)2

= 65+2[ 14+3(16) ]

= 65 + 2(62)

= 65 + 124

= 189 g/mol

mass

= mol × molar mass

= 0.2 mol × 189 g/mol

= 37.8 g

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