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Suppose that the market demand curve for bean sprouts is given by P = 1,660 - 4Q, where P is the price and Q is total industry output. Suppose that the industry has two firms, a Stackleberg leader and a follower. Each firm has a constant marginal cost of $60 per unit of output. In equilibrium, total output by the two firms will be:_______.a. 200. b. 400. c. 50. d. 100. e. 300.

Sagot :

Answer:

In equilibrium, total output by the two firms will be option e= 300.  

Q = [tex]q_{1}[/tex] + [tex]q_{2}[/tex]

Q = 100 + 200

Q = 300

Explanation:

Data Given:

Market Demand Curve = P = 1660-4Q

where, P = price and Q = total industry output

Each firm's marginal cost = $60 per unit of output

So, we know that Q =  [tex]q_{1}[/tex] + [tex]q_{2}[/tex]

where [tex]q_{}[/tex] being the individual firm output.

Solution:

P = 1660-4Q

P = 1660- 4([tex]q_{1}[/tex] + [tex]q_{2}[/tex])

P = 1660 - 4[tex]q_{1}[/tex] - 4[tex]q_{2}[/tex]

Including the marginal cost of firm 1 and multiplying the whole equation by [tex]q_{1}[/tex]

Let's suppose new equation is X

X =  1660[tex]q_{1}[/tex] - 4[tex]q_{1} ^{2}[/tex] - 4[tex]q_{1}[/tex][tex]q_{2}[/tex] - 60[tex]q_{1}[/tex]

Taking the derivative w.r.t to [tex]q_{1}[/tex], we will get:

[tex]X^{'}[/tex] = 1660 - 8[tex]q_{1}[/tex] - 4[tex]q_{2}[/tex] - 60 = 0

Making rearrangements into the equation:

8[tex]q_{1}[/tex] + [tex]q_{2}[/tex] = 1660 - 60

8[tex]q_{1}[/tex] + [tex]q_{2}[/tex] = 1600

Dividing the whole equation by 4

2[tex]q_{1}[/tex] +[tex]q_{2}[/tex] = 400

Solving for [tex]q_{1}[/tex]

2[tex]q_{1}[/tex] = 400 - [tex]q_{2}[/tex]

[tex]q_{1}[/tex] = 200 - 0.5 [tex]q_{2}[/tex]  

Including the marginal cost of firm 1 and multiplying the whole equation by [tex]q_{2}[/tex]

P = 1660 - 4[tex]q_{1}[/tex] - 4[tex]q_{2}[/tex]

Let's suppose new equation is Y

Y =  1660[tex]q_{2}[/tex] - 4[tex]q_{1}[/tex][tex]q_{2}[/tex] -4[tex]q_{2} ^{2}[/tex] - 60[tex]q_{2}[/tex]

Pugging in the value of [tex]q_{1}[/tex]

Y =  1660[tex]q_{2}[/tex] - 4[tex]q_{2}[/tex](200 - 0.5 [tex]q_{2}[/tex]) -4[tex]q_{2} ^{2}[/tex] - 60[tex]q_{2}[/tex]

Y =  1660[tex]q_{2}[/tex] - 800[tex]q_{2}[/tex] +2[tex]q_{2} ^{2}[/tex] -4[tex]q_{2} ^{2}[/tex] - 60[tex]q_{2}[/tex]

Y =  1600[tex]q_{2}[/tex] - 800[tex]q_{2}[/tex] -2[tex]q_{2} ^{2}[/tex]

Taking the derivative w.r.t [tex]q_{2}[/tex]

[tex]Y^{'}[/tex] = 1600 - 800 - 4[tex]q_{2}[/tex] = 0

Solving for [tex]q_{2}[/tex]

4[tex]q_{2}[/tex] = 800

[tex]q_{2}[/tex] = 200

[tex]q_{1}[/tex] = 200 - 0.5 [tex]q_{2}[/tex]

Plugging in the value of [tex]q_{2}[/tex] to get the value of [tex]q_{1}[/tex]

[tex]q_{1}[/tex] = 200 - 0.5 (200)

[tex]q_{1}[/tex] = 200 - 100

[tex]q_{1}[/tex] = 100

Q = [tex]q_{1}[/tex] + [tex]q_{2}[/tex]

Q = 100 + 200

Q = 300

Hence, in equilibrium, total output by the two firms will be option

e= 300.

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