Answer:
1 µC
Explanation:
From the question given above, the following data were obtained:
Electric field intensity (E) = 9000 N/C
Distance (r) = 1 m
Charge (Q) =?
NOTE: Electric force constant (K) = 9×10⁹ Nm²C¯²
The magnitude of the point charge can be obtained as follow:
E = KQ/r²
9000 = 9×10⁹ × Q / 1²
9000 = 9×10⁹ × Q
Divide both side by 9×10⁹
Q = 9000 / 9×10⁹
Q = 1×10¯⁶ C
Recall:
1 micro charge (µC) = 1×10¯⁶ C
Hence, the magnitude of the point charge is 1 µC
Answer:
Explanation:
The magnitude of the point charge is expressed as;
V = kQ/r
k is the coulombs constant = 9.0×10^9 N⋅m²/C²
V is the electric field = 9000N/C
Q is the charge
r is the distance = 1.00m
Get the required charge
Substitute the given parameters into the formula;
9000 = 9.0×10^9Q/1.0
9000 = 9.0×10^9Q
Q = 9000/9.0×10^9
Q = 9.0×10^3/9.0×10^9
Q = 9.0/9.0×10^(3-9)
Q = 1.0×10^6C
Q = 1ηC
hence the magnitude of the point charge is 1ηC
