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Sagot :
Answer:
0.0384
Step-by-step explanation:
Given that:
Mean (m) = 6.0
Standard deviation (s) = 2.0
Sample size (n) = 50
Probability that average amount is greater than 6.5
P(x > 6.5)
Obtain the Zscore using the relation :
Zscore = (x - m) / (s / sqrt(n))
Zscore = (6.5 - 6.0) / (2 / sqrt(50))
Zscore = 0.5 / 0.2828427
Zscore = 1.7677
Zscore = 1.77
P(Z > 1.77) = 1 - P(Z < 1.77)
P(Z > 1.77) = 1 - 0.9616
P(Z > 1.77) = 0.0384
Answer:
4.2%
Step-by-step explanation:
n=50, X=6.0, δ=2.0
Z=[tex]\frac{6.5-6.0}{2.0}[/tex] = 0.25
F(Z)= 4.2% based on the chart in the FE Handbook
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