wyeung1000
Answered

Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Ask your questions and receive precise answers from experienced professionals across different disciplines. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

The perimeter of a rectangle is 162 inches. what are the dimensions of the rectangle if the length is 7 times than 3 times the width?​

Sagot :

Answer:

3.68 inches × 77.28 inches

Step-by-step explanation:

Given that,

The perimeter of a rectangle is 162 inches.

Let the width is b.

ATQ,

Length = 7 times than 3 times the width

l = 7(3b) = 21b ...(1)

The perimeter of a rectangle is given by :

P = 2(l+b)

Put all the values,

162 = 2(21b+b)

81 = 22b

b = 3.68 inches

Put the value of b in equation (1)

l = 21b

= 21 (3.68)

= 77.28 inches

Hence, the dimensions of the rectangle are 3.68 inches × 77.28 inches

Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.