americanfailure
Answered

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GIVING BRAINLY OUT FOR WHOEVER IS CORRECT AND FAST!
The length of a rectangle is twice as long as it's width. The perimeter of this rectangle is how many times longer than the shorter side?

Sagot :

goldenpoo21
The formula for perimeter is the sum of
twice the width and twice the length, so
the formula would be:
Perimeter = 2W + 2L

In this problem:
Width is unknown (x)
Length is twice the width (2x)
and Perimeter = 60, so to set it up:
60 = 2x + 2(2x)
60 = 2x + 4x
60 = 6x
x = 10
Width = 10; Length = 20

Answer:

The formula for perimeter is the sum of

twice the width and twice the length, so

the formula would be:

Perimeter = 2W + 2L

In this problem:

Width is unknown (x)

Length is twice the width (2x)

and Perimeter = 60, so to set it up:

60 = 2x + 2(2x)

60 = 2x + 4x

60 = 6x

x = 10

Width = 10; Length = 20

So then you do 20/10

= 2

2 is the answer

Step-by-step explanation:

Hope this helps,

Please give brainliest if you like my answer.

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