Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Explore in-depth answers to your questions from a knowledgeable community of experts across different fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Answer:
Answer:
1. The confidence interval for the difference of means weight gain using 76 as the degree of freedom is -1.664, 5.664
2.The calculated value of t does not lie in the critical region for both d.f 76 and 83 . Therefore we accept our null hypothesis that pigs fed with Diet A gain more weight than with diet B at the 0.05 level
Step-by-step explanation:
# Pigs Mean Weight Gain Standard Deviation
Diet A 36 55 3
Diet B 49 53 5.6
(x`1- x` The 2) ± t∝/2 (v) . Sp √1/n1 + 1/n2
where v= d.f= 76
Here the difference between the sample means is x`1- x`2= 55-53= 2
The pooled estimate for the common variance σ² is
Sp² = 1/n1+n2 -2 [ ∑ (x1i - x1`)² + ∑ (x2j - x`2)²]
= 1/36 +49-2 [ 55²+53²]
Sp = √3025 +2809/83 = 8.38
t (0.025) (76) = 1.992
(x`1- x`2)± t∝/2 (v) . Sp √1/n1 + 1/n2
(2 )± 1.992 (8.38) √ 1/36 + 1/49
(2 )± 3.664
-1.664, 5.664
Par t 2:
The null and alternate hypotheses are
H0 : u1 > u2 against Ha: u1 ≤ u 2
Significance level alpha = 0.05
The critical region t ≥ t (0.05, 76) = 1.665
D.f = n1+n2- 2= 83
The critical region t ≥ t (0.05, 83) = 1.663
t = (x`1- x` ) /. Sp √1/n1 + 1/n2
t= 2/ 8.38 √1/36+ 1/49
t= 2/1.839
t= 1.087
The calculated value of t does not lie in the critical region for both d.f 76 and 83 . Therefore we accept our null hypothesis that pigs fed with Diet A gain more weight than with diet B at the 0.05 level
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.