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Sagot :
Step-by-step explanation:
x/(x + 2) + 1/x = 1
x² + (x + 2) = x(x + 2)
x² + x + 2 = x² + 2x
x = 2.
Since x = 2 neither makes (x + 2) or x become 0, there are no extraneous solutions.
The answer is "The equation has 1 valid solution and no extraneous solutions." (C)
The true statement is (c) the equation has one valid solution and no extraneous solutions
The equation is given as:
[tex]\frac{x}{x + 2} + \frac 1x = 1[/tex]
Take LCM
[tex]\frac{x^2 + x + 2}{x(x + 2)} = 1[/tex]
Expand the numerator
[tex]\frac{x^2 + x + 2}{x^2 + 2x} = 1[/tex]
Cross multiply
[tex]x^2 + x + 2 = x^2 + 2x[/tex]
Subtract x^2 from both sides
[tex]x + 2 = 2x[/tex]
Collect like terms
[tex]2x -x = 2[/tex]
[tex]x = 2[/tex]
Hence, the equation has one valid solution and no extraneous solutions
Read more about solutions of equations at:
https://brainly.com/question/1397278
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