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Sagot :
2y+4x=12
Move 4x to the other side as a negative number
2y=-4x+12
Divide all terms by 2
y=-2x+6
Now, in order for two lines to be perpendicular, their gradients have to multiply obeyed to get -1 (let a be the gradient of the given line and let b be the gradient of the line we're trying to find)
So, we do -2*b=-1
so, b is equal to 1/2
Now, we are given a coordinate so we substitute it in y-y1=m(x-x1)
y-1=1/2(x-8)
Expand brackets
y-1= 1/2x-4
Take -1 to the other side as a positive number
y=1/2x-3
So, the equation of the line is y=1/2x-3
Move 4x to the other side as a negative number
2y=-4x+12
Divide all terms by 2
y=-2x+6
Now, in order for two lines to be perpendicular, their gradients have to multiply obeyed to get -1 (let a be the gradient of the given line and let b be the gradient of the line we're trying to find)
So, we do -2*b=-1
so, b is equal to 1/2
Now, we are given a coordinate so we substitute it in y-y1=m(x-x1)
y-1=1/2(x-8)
Expand brackets
y-1= 1/2x-4
Take -1 to the other side as a positive number
y=1/2x-3
So, the equation of the line is y=1/2x-3
Answer:
1/2x-3
Step-by-step explanation:
First, make the equation 2y+4x=12 into a linear equation(y=mx+b)
2y=-4x+12
y=-2x+6
From this, you know the slope is -2.
The perpendicular of any slope is going to be the negative inverse.
negative inverse: a/b-->-b/a
so basically flip it and make it negative(make it positive if the original is negative).
So, for -2 it would be 1/2
Now right the equation for the perpendicular line.
y=1/2x+b
b is the y intercept, and since you want to make the line go through (8,1) you have to change the 6 in the original equation.
To do this replace x and y with 8 and 1
1=1/2(8)+b
1=4+b
b=-3
So you plug that into the equation
y=1/2x-3
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