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Aluminum reacts with chlorine gas to form aluminum chloride
via the following reaction:
2A1 + 3Cl2 + 2AlCl3
How many grams of aluminum chloride could be produced by
reacting 34.0 g of aluminum and 39.0 g of chlorine gas?

Sagot :

Mass is the multiplication product of moles and the molar mass of the substance. The mass of aluminum chloride in the reaction is 48.95g.

What are grams?

Grams are the unit of the measurement of the substance used to calculate the weight of the substance in a compound or molecule.

The balanced chemical reaction is  given as:

[tex]\rm 2Al (s) + 3Cl_{2} (g) \rightarrow 2AlCl_{3} (s)[/tex]

Given,

Mass of aluminium = 34.0 gm

Mass of chlorine gas = 39.0 gm

The moles of aluminum is calculated as:

[tex]\dfrac{34}{27} = 1.26[/tex]

The moles of chlorine gas are calculated as:

[tex]\dfrac{39}{2 \times 35.5} = 0.55[/tex]

From the moles, it can be seen that aluminum is in excess so further calculations will be done based on the moles of chlorine gas.

Moles of aluminum chloride are calculated as:

[tex]\dfrac{0.5500 \;\rm mol \; Cl_{2} \times 2 \;\rm mol \; AlCl_{3}}{3 \;\rm mol \; Cl_{2}} = 0.3667 \;\rm mol \;\rm AlCl_{3}[/tex]

Moles of aluminum chloride are 0.3667 and the molar mass is 133.341 g/mol. The mass is calculated as:

[tex]0.3667 \times 133.341 = 48.8961[/tex]

Therefore, 48.95 gm is the mass of aluminum chloride.

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