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The time period, T, of a simple pendulum is directly proportional to the square root of the length, d, of the pendulum.

When d=6, T=5

Find the value of T when d=3

Input note: give your answer correct to 2 decimal place.

Sagot :

tutorAnne

Answer: T= 3.54

Step-by-step explanation:

Step 1

Given that

The time period, T, s doirectly proportional  to the square root of the length, d, of the pendulum, we have that

T  ∝  [tex]\sqrt{d}[/tex]

Introducing the constant of proportionality, we have that

T= K[tex]\sqrt{d}[/tex].

Step 2

When d=6, T=5, K =?

T= K[tex]\sqrt{d}[/tex].

5 = k[tex]\sqrt{6}[/tex]

5=  k x 2.44949

k =5/2.44949

k =2.041

Therefore, when d = 3 , T= ?

T= K[tex]\sqrt{d}[/tex]

T= 2.041 x [tex]\sqrt{3}[/tex]

T= 3.53511≈ 3.54

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