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A tornado drops a piece of wood from a
height of 4,624 ft. If the equation for
height as a function of time is
h(t) = -16t2 + initial height where t is time
in seconds and h(t) is height in feet, how
many seconds will it take for the piece of
wood to hit the ground?

Sagot :

Answer:

Step-by-step explanation:

H(t) =  -16[tex]t^{2}[/tex]+4.624  ( in feet)

0 = -16[tex]t^{2}[/tex] + 4,624

-4,624 =  -16[tex]t^{2}[/tex]

-4,624 / -16 = [tex]t^{2}[/tex]

289 = [tex]t^{2}[/tex]

17 = t

so.. 17 seconds to hit the ground..  :)

The piece of wood 17 seconds takes to hit the ground.

What are Arithmetic operations?

Arithmetic operations can also be specified by adding, subtracting, dividing, and multiplying built-in functions. The operator that performs the arithmetic operation is called the arithmetic operator.

A tornado drops a piece of wood from a height of 4,624 ft.

Given that the equation for the height as a function of time is

h(t) = -16t² + initial height

Substitute height = 4,624 ft. in the equation,

h(t) =  -16t² +4.624

At ground level, the value of h(t) is zero,

0 = -16t² + 4,624

16t² = 4,624

t² = 4,624/16

t² =289

t = 17

So, 17 seconds to hit the ground

Hence, the piece of wood 17 seconds takes to hit the ground.

Learn more about Arithmetic operations here:

https://brainly.com/question/25834626

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