Answered

At Westonci.ca, we connect you with the answers you need, thanks to our active and informed community. Explore a wealth of knowledge from professionals across various disciplines on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A drop of oil makes a circular ring in a water puddle. The radius of the oil ring expands at 1.5 cm per second. If r(t)=1.5t and a(r)=лr^2, what composition of function describes the area of the oil ring in terms of time?

Sagot :

MrRoyal

Answer:

[tex]a(t) =n(0.25t^2)[/tex]

Step-by-step explanation:

Given

[tex]r(t) = 0.5t[/tex]

[tex]a(r) = nr^2[/tex]

Required

Determine the area in terms of time

From the question, we have:

[tex]r(t) = 0.5t[/tex] -> radius per time

and

[tex]a(r) = nr^2[/tex] --> area from radius

The interpretation of the question is to find the composite function: a(t)

If [tex]a(r) = nr^2[/tex], and [tex]r(t) = 0.5t[/tex], the

Substitute 0.5t for r

[tex]a(t) =n(0.5t)^2[/tex]

[tex]a(t) =n*0.25t^2[/tex]

[tex]a(t) =n(0.25t^2)[/tex]

Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.