Answer:
Mei descends faster
Mei's height decreases 5ft every second
Victor's height decreases 3.33 ft every second
Step-by-step explanation:
Given
Mel
[tex](x_1,y_1) = (2,50)[/tex]
[tex](x_2,y_2) = (5,35)[/tex]
Victor
[tex](x_1,y_1) = (1,60)[/tex]
[tex](x_2,y_2) = (4,50)[/tex]
Required
Who descend faster?
To do this, we simply calculate the slope/rate of both individuals
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
For Mei:
[tex]m_1 = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex](x_1,y_1) = (2,50)[/tex]
[tex](x_2,y_2) = (5,35)[/tex]
[tex]m_1 = \frac{35 -50}{5 - 2}[/tex]
[tex]m_1 = \frac{-15}{3}[/tex]
[tex]m_1 = -5[/tex]
Mei descends at 5ft per second
For Victor:
[tex]m_2 = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex](x_1,y_1) = (1,60)[/tex]
[tex](x_2,y_2) = (4,50)[/tex]
[tex]m_2 = \frac{50-60}{4 - 1}[/tex]
[tex]m_2 = \frac{-10}{3}[/tex]
[tex]m_2 = -3.33[/tex]
Victor descends at 3.33ft per second
By comparison:
Mei descends faster
