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2. A lever has efficiency 60% and mechanical advantage 4, then
(i) Calculate effort required to lift 1000 N load. [250 N] (ii
(ii) Calculate velocity ratio of the lever. [VR = 6.66]
(iii) Find out output work to turn load up to 20 m. [20,000 Nm]
1:0​

Sagot :

olayemiolakunle65

Answer:

(i) Effort = 250 N

(ii) Velocity ratio = 6.667

(iii) work output = 20 000 Nm

Explanation:

Given: efficiency = 60%, mechanical advantage = 4.

(i) Mechanical advantage = [tex]\frac{Load}{effort}[/tex]

Load = 1000 N

⇒ Effort = [tex]\frac{Load}{Mechanical advantage}[/tex]

             = [tex]\frac{1000}{4}[/tex]

             = 250 N

Effort = 250 N

(ii) Efficiency = [tex]\frac{Mechanical advantage}{velocity ratio}[/tex] x 100%

Velocity ratio = [tex]\frac{Mechanical advantage}{Efficiency}[/tex] x 100%

                      = [tex]\frac{4}{60}[/tex] x 100

                      = 6.667

Velocity ratio = 6.667

(iii) Work output = Load x distance moved by load

                         = 1000 x 20

                         = 20 000

Work output = 20 000 Nm

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