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i)1-2(2x+1)=1-(x-1)
ii)3.6x-6.1=5.9_2.4x
question from equation and inequality​

Sagot :

absor201

Answer:

1)Solving the expression [tex]1-2(2x+1)=1-(x-1)[/tex] we get [tex]\mathbf{x=-\frac{1}{3}}[/tex]

2) solving the equation [tex]3.6x-6.1=5.9-2.4x[/tex] we get [tex]\mathbf{x=2}[/tex]

Step-by-step explanation:

We need to solve the expressions:

1) [tex]1-2(2x+1)=1-(x-1)\\[/tex]

Solving

[tex]1-2(2x+1)=1-(x-1)[/tex]

First solving the brackets

[tex]1-4x-2=1-x+1[/tex]

Simplifying

[tex]-1-4x=-x[/tex]

Adding 4x on both sides

[tex]-1-4x+4x=-x+4x\\-1=3x[/tex]

Switching the sides

[tex]3x=-1[/tex]

Divide both sides by 3

[tex]\frac{3x}{3}=-\frac{1}{3}\\x= -\frac{1}{3}[/tex]

So, Solving the expression [tex]1-2(2x+1)=1-(x-1)[/tex] we get [tex]\mathbf{x=-\frac{1}{3}}[/tex]

2) [tex]3.6x-6.1=5.9-2.4x[/tex]

Solving:

[tex]3.6x-6.1=5.9-2.4x[/tex]

Adding 6.1 on both sides

[tex]3.6x-6.1+6.1=5.9-2.4x+6.1\\3.6x=12-2.4x[/tex]

Adding 2.4x on both sides

[tex]3.6x+2.4x=12-2.4x+2.4x\\6x=12\\[/tex]

Divide both sides by 6

[tex]\frac{6x}{6}=\frac{12}{6}\\x=2[/tex]

So, solving the equation [tex]3.6x-6.1=5.9-2.4x[/tex] we get [tex]\mathbf{x=2}[/tex]

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